-16t^2+240t-704t=0

Solution for -16t^2+240t-704t=0 equation:

-16t^2+240t-704t=0

We add all the numbers together, and all the variables

-16t^2-464t=0

a = -16; b = -464; c = 0;
Δ = b2-4ac
Δ = -4642-4·(-16)·0
Δ = 215296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{215296}=464$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-464)-464}{2*-16}=\frac{0}{-32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-464)+464}{2*-16}=\frac{928}{-32}
=-29
$